# Integral Effect on Control System This dir is belong to Control System class contains with Integral Effect on Control System. This code 100% original made by my hand :), please leave some notes if you're going to use it. Thanks! ## Software This program ran in Matlab ## Variables `s = tf('s');` defines s as 'frequency domain' for transfer function and will be used further. ``` J = 0.01; b = 0.1; K = 0.01; R = 1; L = 0.5; ``` Those variable comes from BLDC control system. ``` Kp = 1; % Ki = 1; % Ki = 3; % Ki = 5; Ki = 7; % Ki = 9; ``` Variable above is the constant from PI control, we're trying to varies the constant to analyze integral effect on control system ## Process The BLDC motor control system should be defined as transfer function by initialize its numerator-denumerator and *tf()* function. ``` num_motor = [K]; den_motor = [J*L J*R+b*L R*b+K*K]; motor = tf(num_motor,den_motor) ``` Besides the plant function, the PI-control system defined by `C = tf([Kp Ki],[1 0])`. The vector is set according to PI formula which `PI = Kp * Ki/s`. After that, both of system are multiplied each others without feedback by `complete = feedback(motor*C,1);` That system will be test with step, ramp, and impulse input by call below lines ``` subplot(311), impulse(complete); % Impulse reponse subplot(312), step(complete); % Step Response subplot(313), step(complete / s); % Ramp response stepinfo(complete) ``` Since Matlab doesn't provide any steady-state error calculation, we process it by call below lines ``` [y,t] = step(complete); % Calculate Steady-State error sse = abs(1 - y(end)) ``` Last line works to limit the graph ``` xlim([0 50]) ylim([0 3]) ``` ## Testing For Kp = 1 | Param | Ki = 1 | Ki = 3 | Ki = 5 | Ki = 7 | Ki = 9 | |--- |--- |--- |--- |--- |--- | | Rise Time | 22.7723 | 6.7782 | 3.5914 | 2.3175 | 2.3175 | | Settling Time | 40.3716 | 12.1907 | 6.3158 | 3.6779 | 3.6779 | | Overshoot | 0 | 0 | 0 | 0.3523 | 0 | | SSE | 1.7396e-06 | 0.0034 | 0.0033 | 0.0034 | 6.6536e-05 | Notes: In theory, SSE should decrease following the increased Ki, but i suspect Matlab just can't compute too much floating point. Hence, i add two additional test with larger constant to show the effects. ## Additional Testing For Kp = 50 | Param | Ki = 0 | Ki = 5 | |--- |--- |--- | | Rise Time | 0.1201 | 0.1415 | | Settling Time | 0.6376 | 29.5503 | | Overshoot | 19.6150 | 6.1627 | | SSE | 0.1127 | 0.0082 | ## Conclusion Based on previous tests, we conclude that by adding Integral constant : * Risie time is **increased** * Settling time is **increased** * Overshoot is **decreased** * SSE is **decreased** ### Notes Contact nanda.r.d@mail.ugm.ac.id for more information ### Links You can access the source code here [github.com/nandard/routh_table.git](https://github.com/nandard/routh_table.git)